Chemistry · Redox Reactions

JEE Main 2024 — 1 February, Shift 1 — Question 59

In acidic medium, K2Cr2O7\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} shows oxidising action as represented in the half reaction

Cr2O72−+XH++Ye−→2 A+ZH2O\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+\mathrm{XH}^{+}+\mathrm{Ye}^{-} \rightarrow 2 \mathrm{~A}+\mathrm{ZH}_{2} \mathrm{O} X,Y,Z\mathrm{X}, \mathrm{Y}, \mathrm{Z} and A are respectively are:

  1. Option A:

    8,6,48,6,4 and Cr2O3\mathrm{Cr}_{2} \mathrm{O}_{3}

  2. Option B:

    14, 7, 6 and Cr3+\mathrm{Cr}^{3+}

  3. Option C:

    8,4,68,4,6 and Cr2O3\mathrm{Cr}_{2} \mathrm{O}_{3}

  4. Option D:

    14,6,714,6,7 and Cr3+\mathrm{Cr}^{3+}

    Correct

Answer: D

Step-by-step solution

The balanced reaction is,

Cr2O72−+14H++6e−→2Cr3++7H2O\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_{2} \mathrm{O}

X=14\mathrm{X}=14

Y=6\mathrm{Y}=6

A=7\mathrm{A}=7

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Redox Reactions
Topic
Types of Redox Reactions & Balancing of Redox Reactions
In acidic medium, K 2 Cr 2 O 7 shows oxidising action as represented… | JEE Main 2024 PYQ with Solution · DhiX AI