Mathematics · Trigonometry Ratios and Identities

JEE Main 2024 — 8 April, Shift 1 — Question 11

If sinx=−35\text{sin}x=-\frac{3}{5}, where π<x<3π2\pi <x<\frac{3\pi }{2}, then 80(tan2x−cosx)80\left( \text{ta}{{\text{n}}^{2}}x-\text{cos}x \right) is equal to :

  1. Option A:

    109

    Correct
  2. Option B:

    108

  3. Option C:

    18

  4. Option D:

    19

Answer: A

Step-by-step solution

sinx=−35,π< x<3π2\text{sin}x=\frac{-3}{5},\pi <\ x<\frac{3\pi }{2} tanx=34\text{tan}x=\frac{3}{4}

cosx=−45\text{cos}x=-\frac{4}{5} 80(tan2x−cosx)80\left( \text{ta}{{\text{n}}^{2}}x-\text{cos}x \right) =80(916+45)=45+64=109=80\left( \frac{9}{16}+\frac{4}{5} \right)=45+64=109

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Trigonometry Ratios and Identities
Topic
Trigonometric Ratios of Allied Angles