Mathematics · Matrices

JEE Main 2026 — 21 January, Evening Shift — Question 18

If the system of equations 3x+y+4z=33 x+y+4 z=3, 2x+αy−z=−32 \mathrm{x}+\alpha \mathrm{y}-\mathrm{z}=-3, X+2y+z=4\mathrm{X}+2 \mathrm{y}+\mathrm{z}=4 has no solution, then the value of α\alpha is equal to:

  1. Option A:

    1919

    Correct
  2. Option B:

    44

  3. Option C:

    1313

  4. Option D:

    2323

Answer: A

Step-by-step solution

for no solution Δ=0\Delta=0

∣3142α−1121∣=0\left|\begin{array}{ccc}3 & 1 & 4 \\2 & \alpha & -1 \\1 & 2 & 1\end{array}\right|=0

⇒3(a+2)+1(−1−2)+4(4−α)=0\Rightarrow 3(\mathrm{a}+2)+1(-1-2)+4(4-\alpha)=0

⇒19−α=0⇒α=19\Rightarrow 19-\alpha=0 \Rightarrow \alpha=19 & for α=19\alpha=19

Δx=∣314−319−1421∣=3(21)+1(−1)+4(−82)\Delta_{\mathrm{x}}=\left|\begin{array}{ccc}3 & 1 & 4 \\-3 & 19 & -1 \\4 & 2 & 1\end{array}\right|=3(21)+1(-1)+4(-82)

≠0\neq 0 ∴ no solution for α=19\alpha=19

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Matrices
Topic
solving System of Linear Equations using Matrices
If the system of equations 3 x+y+4 z=3 , 2 x +α y - z =-3 , X +2 y +… | JEE Main 2026 PYQ with Solution · DhiX AI