Mathematics · Matrices

JEE Main 2026 — 21 January, Evening Shift — Question 14

For the matrices A=[3−41−1]\mathrm{A}=\left[\begin{array}{ll}3 & -4 \\1 & -1\end{array}\right] and B=[−2949−1318]\mathrm{B}=\left[\begin{array}{ll}-29 & 49 \\-13 & 18\end{array}\right], if (A15+B)[xy]=[00]\left(\mathrm{A}^{15}+\mathrm{B}\right)\left[\begin{array}{l}\mathrm{x}\\ \mathrm{y}\end{array}\right]=\left[\begin{array}{l}0\\ 0\end{array}\right], then among the following which one is true?

  1. Option A:

    x=5,y=7\mathrm{x}=5, \mathrm{y}=7

  2. Option B:

    x=18,y=11\mathrm{x}=18, \mathrm{y}=11

  3. Option C:

    x=11,y=2x=11, y=2

    Correct
  4. Option D:

    x=16,y=3x=16, y=3

Answer: C

Step-by-step solution

Here An=[2n+1−4nn−2n+1]A^{n}=\left[\begin{array}{cc}2 n+1 & -4 n \\n & -2 n+1\end{array}\right]

⇒A15=[31−6015−29]\Rightarrow \mathrm{A}^{15}=\left[\begin{array}{ll}31 & -60 \\15 & -29\end{array}\right]

⇒A15+B=[2−112−11]\Rightarrow \mathrm{A}^{15}+\mathrm{B}=\left[\begin{array}{ll}2 & -11 \\2 & -11\end{array}\right]

Now (A15+B)[xy]=[00]\left(A^{15}+B\right)\left[\begin{array}{l}x y\end{array}\right]=\left[\begin{array}{l}0 \\0\end{array}\right]

⇒[2−112−11][xy]=[00]\Rightarrow\left[\begin{array}{cc}2 & -11\\ 2 & -11\end{array}\right]\left[\begin{array}{l}\mathrm{x} \\\mathrm{y}\end{array}\right]=\left[\begin{array}{l}0 \\0\end{array}\right]

⇒2x−11y=0\Rightarrow 2 \mathrm{x}-11 \mathrm{y}=0

x=11,y=2x=11, y=2

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Matrices
Topic
Characteristic Equation & roots,application of cayley - hamilton theorem
For the matrices A = [begin array ll 3 & -4 \\1 & -1end array ] and B… | JEE Main 2026 PYQ with Solution · DhiX AI