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Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2026 — 5 April, Morning Shift — Question 49

How many grams of residue is obtained by heating 2.76 g of silver carbonate? (Given : Molar mass of C,O\mathrm{C}, \mathrm{O} and Ag are 12, 16 and 108 g mol−1108 \mathrm{~g} \mathrm{~mol}^{-1} respectively)

  1. Option A:

    1.08 g

  2. Option B:

    2.16 g

    Correct
  3. Option C:

    3.24 g

  4. Option D:

    4.32 g

Answer: B

Step-by-step solution

Ag2CO3( s)→Δ2Ag(s)+CO2( g)+12O2( g)\quad \mathrm{Ag}_{2} \mathrm{CO}_{3}(\mathrm{~s}) \xrightarrow{\Delta} 2 \mathrm{Ag}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) 2.76g 1100\frac{1}{100} mol Moles of Ag⁡(s)=2100 mol\operatorname{Ag}(\mathrm{s})=\frac{2}{100} \mathrm{~mol} Mass of residue =2.16 g=2.16 \mathrm{~g}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
5 April, Morning Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Chemical Equations, Stoichiometry and Limiting Reagent

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