Arrange the following atomic orbitals of multi electron atoms in order of increasing energy. (A) n =3, ell=2, m =+1 (B) n=4, ell=0, m=0 (C) n =6, ell=1, m =0 (D) n =5, ell=1, m =+1 (E) n =2, ell=1, m =+1 Choose the correct answer from the options given below :

Chemistry · Structure of Atom

JEE Main 2026 — 5 April, Morning Shift — Question 50

Arrange the following atomic orbitals of multi electron atoms in order of increasing energy. (A) $\mathrm{n}=3, \ell=2, \mathrm{~m}=+1$ (B) $n=4, \ell=0, m=0$ (C) $\mathrm{n}=6, \ell=1, \mathrm{~m}=0$ (D) $\mathrm{n}=5, \ell=1, \mathrm{~m}=+1$ (E) $\mathrm{n}=2, \ell=1, \mathrm{~m}=+1$

Choose the correct answer from the options given below :

Option A:
C $<$ D $<$ B $<$ A $<$ E
Option B:
B $<$ A $<$ E $<$ C $<$ D
Option C:
E $<$ C $<$ D $<$ B $<$ A
Option D:
E $<$ B $<$ A $<$ D $<$ C
Correct

Answer: D

Step-by-step solution

(A) $\mathrm{n}=3,\ \mathrm{l}=2,\ \mathrm{m}=+1;\quad (\mathrm{n}+\mathrm{l})=5$

(B) $\mathrm{n}=4,\ \mathrm{l}=0,\ \mathrm{m}=0;\quad (\mathrm{n}+\mathrm{l})=4$

(D) $\mathrm{n}=5,\ \mathrm{l}=1,\ \mathrm{m}=+1;\quad (\mathrm{n}+\mathrm{l})=6$

(E) $\mathrm{n}=2,\ \mathrm{l}=1,\ \mathrm{m}=+1;\quad (\mathrm{n}+\mathrm{l})=3$

More the value of $(\mathrm{n}+\mathrm{l})$ , more will be the energy of that particular orbital.

Ans. $\mathrm{E}<\mathrm{B}<\mathrm{A}<\mathrm{D}<\mathrm{C}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 5 April, Morning Shift
Subject: Chemistry
Chapter: Structure of Atom
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Step-by-step solution

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