Physics · Thermodynamics

JEE Main 2026 — 2 April, Morning Shift — Question 6

Heat is supplied to a diatomic gas at constant pressure. Then the ratio of $\Delta \mathrm{Q}:\Delta \mathrm{U}:\Delta \mathrm{W}$ is

Option A:
$2:3:5$
Option B:
$5:3:2$
Option C:
$2:5:7$
Option D:
$7:5:2$
Correct

Answer: D

Step-by-step solution

$\Delta \mathrm{Q}_{\mathrm{p}} = \mathrm{nC}_{\mathrm{p}}\Delta \mathrm{T} = \frac{7}{2}\mathrm{nR}\Delta \mathrm{T}$ , $\Delta \mathrm{U} = \mathrm{nC}_{\mathrm{A}}\Delta \mathrm{T} = \frac{5}{2}\mathrm{nR}\Delta \mathrm{T}$ , $\mathrm{W} = \mathrm{nR}\Delta \mathrm{T}$ → ratio 7:5:2

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 2 April, Morning Shift
Subject: Physics
Chapter: Thermodynamics
Topic: First Law of Thermodynamics

A vessel contains 0.15 m^3 of a gas at pressure 8 bar and temperature 140^circ C with c p = 3 R and c v = 2 R . It is expanded…

Answer: D

Step-by-step solution

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