A particle is rotating in a circular path and at any instant its motion can be described as θ = frac 5 t 4 40 -frac t 3 3 The angular acceleration of the particle after 10 seconds is rad/s2.

Physics · Horizontal Circular Motion

JEE Main 2026 — 2 April, Morning Shift — Question 5

A particle is rotating in a circular path and at any instant its motion can be described as $\theta = \frac{5\mathrm{t}^{4}}{40} -\frac{\mathrm{t}^{3}}{3}$ The angular acceleration of the particle after 10 seconds is rad/s2.

Option A:
150
Option B:
120
Option C:
130
Correct
Option D:
170

Answer: C

Step-by-step solution

$\frac{\mathrm{d}\theta}{\mathrm{d}t} = \frac{\mathrm{t}^{3}}{2} -\mathrm{t}^{2}$ $\alpha = \frac{3\mathrm{t}^{2}}{2} -2\mathrm{t}$ at $\mathrm{t}=10$ , $\alpha = 130$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 2 April, Morning Shift
Subject: Physics
Chapter: Horizontal Circular Motion
Topic: Introduction to Angular variables