Physics · Electrostatics

JEE Main 2024 — 27 January, Shift 2 — Question 47

Given below are two statements : one is labelled a Assertion (A) and the other is labelled as Reason (R)

Assertion (A): Work done by electric field on moving a positive charge on an equipotential surface is always zero.

Reason (R): Electric lines of forces are always perpendicular to equipotential surfaces.

In the light of the above statements, choose the correct answer from the options given below :

Option A:
Both (A) and (R) are true and (R) is the correct explanation of (A).
Correct
Option B:
Both (A) and (R) are true and (R) is NOT the correct explanation of (A).
Option C:
(A) is true but (R) is false.
Option D:
(A) is false but (R) is true.

Answer: A

Electric line of force are always perpendicular to equipotential surface so angle between farce and displacement

will always be $90^{\circ}$ . So work done equal to 0

Answer key and solution verified before publishing.

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