An object is placed in a medium of refractive index 3. An electromagnetic wave of intensity 6 × 10 8 W / m 2 falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space .=3 × 10 8 m / s ) :

Physics · Atomic Physics

JEE Main 2024 — 27 January, Shift 2 — Question 46

An object is placed in a medium of refractive index 3. An electromagnetic wave of intensity $6 \times 10^{8} \mathrm{~W} / \mathrm{m}^{2}$ falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space $\left.=3 \times 10^{8} \mathrm{~m} / \mathrm{s}\right)$ :

Option A:
$36 \mathrm{Nm}^{-2}$
Option B:
$18 \mathrm{Nm}^{-2}$
Option C:
$6 \mathrm{Nm}^{-2}$
Correct
Option D:
$2 \mathrm{Nm}^{-2}$

Answer: C

Step-by-step solution

Radiation pressure $=\frac{\mathrm{I}}{\mathrm{v}}$

$=\frac{I \cdot \mu}{\mathrm{C}}$

$=\frac{6 \times 10^{8} \times 3}{3 \times 10^{8}}$

$=6 \mathrm{~N} / \mathrm{m}^{2}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 27 January, Shift 2
Subject: Physics
Chapter: Atomic Physics
Topic: Photon Theory of Light and Radiation Pressure

Answer: C

Step-by-step solution

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