Consider the following reactions A + NaCl + H 2 SO 4 xrightarrow Little amount CrO 2 Cl 2 + Side Products CrO 2 Cl 2( vapour ) + NaOH rightarrow B + NaCl + H 2 O B + H + rightarrow C + H 2 O The number of terminal ' O ' present in the compound ' C ' is \ \ \ \ \

Chemistry · d and f Block Elements

JEE Main 2025 — 3 April, Morning Shift — Question 19

Consider the following reactions

$\text{A} + \text{NaCl} + \text{H}_2\text{SO}_4 \xrightarrow{\text{Little amount}} \text{CrO}_2\text{Cl}_2 + \text{Side Products}$ $\text{CrO}_2\text{Cl}_{2(\text{vapour})} + \text{NaOH} \rightarrow \text{B} + \text{NaCl} + \text{H}_2\text{O}$ $\text{B} + \text{H}^+ \rightarrow \text{C} + \text{H}_2\text{O}$

The number of terminal ' $O$ ' present in the compound ' $C$ ' is $\_\_\_\_\_$

Answer: 6

Numerical answer — enter this value.

Step-by-step solution

Terminal oxygen atoms $=6$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 3 April, Morning Shift
Subject: Chemistry
Chapter: d and f Block Elements
Topic: Compounds of Chromium