0.5 g of an organic compound on combustion gave 1.46 g of CO 2 and 0.9 g of H 2 O . The percentage of carbon in the compound is \ \ \ \ \ . (Nearest integer) [Given : Molar mass (in g mol -1 ) C : 12, H : 1, O : 16]

Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2025 — 3 April, Morning Shift — Question 18

0.5 g of an organic compound on combustion gave 1.46 g of $\mathrm{CO}_{2}$ and 0.9 g of $\mathrm{H}_{2} \mathrm{O}$ . The percentage of carbon in the compound is $\_\_\_\_\_$ . (Nearest integer) [Given : Molar mass (in $\mathrm{g} \mathrm{mol}^{-1}$ ) $\mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}$ : 16]

Answer: 80

Numerical answer — enter this value.

Step-by-step solution

Mass of $C=\frac{1.46}{44} \times 12=0.398 \mathrm{~g}$

% by mass of $C=\frac{0.398}{0.5} \times 100$

= 79.63%

Nearest integer $=80$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 3 April, Morning Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic: Percentage composition & Empirical Formula

Among 10^-9 g (each) of the following elements, which one will have the highest number of atoms? Elements: Pb, Po, Pr and Pt

Answer: 80

Step-by-step solution

Practise Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

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