At T ( K ) , the equilibrium constant of A 2 ( g )+ B 2 ( g ) rightleftharpoons C ( g ) is 2.7 × 10 -5 . What is the equilibrium constant for 1/3 A 2 ( g )+1/3 B 2 ( g ) rightleftharpoons 1/3 C ( g ) at the same temperature?

Chemistry · Chemical Equilibrium

JEE Main 2026 — 4 April, Morning Shift — Question 52

At $\mathrm{T}(\mathrm{K})$ , the equilibrium constant of $\mathrm{A}_{2}(\mathrm{~g})+\mathrm{B}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{C}(\mathrm{g})$ is $2.7 \times 10^{-5}$ .

What is the equilibrium constant for $\frac{1}{3} \mathrm{~A}_{2}(\mathrm{~g})+\frac{1}{3} \mathrm{~B}_{2}(\mathrm{~g}) \rightleftharpoons \frac{1}{3} \mathrm{C}(\mathrm{g})$ at the same temperature?

Option A:
$\left(2.7 \times 10^{-5}\right)^{3}$
Option B:
$6 \times 10^{-2}$
Option C:
$\sqrt{2.7 \times 10^{-5}}$
Option D:
$3 \times 10^{-2}$
Correct

Answer: D

Step-by-step solution

\begin{aligned} & \frac{1}{3} \mathrm{~A}_{2}(\mathrm{~g})+\frac{1}{3} \mathrm{~B}_{\mathrm{e}}(\mathrm{~g}) \rightleftharpoons \frac{1}{3} \mathrm{C}(\mathrm{~g}) \mathrm{K}_{\mathrm{eq}}^{1}=\left(\mathrm{K}_{\mathrm{eq}}\right)^{1 / 3} & \mathrm{~K}_{\mathrm{eq}}^{1}=\left(2.7 \times 10^{-5}\right)^{1 / 3} & \quad=3 \times 10^{-2} \end{aligned}

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 4 April, Morning Shift
Subject: Chemistry
Chapter: Chemical Equilibrium
Topic: Analysis of Chemical Equilibrium, Equilibrium Constant and Reaction Quotient