Chemistry · Redox Reactions

JEE Main 2026 — 4 April, Morning Shift — Question 53

In order to oxidise a mixture of 1 mole each of FeC2O4,Fe2(C2O4)3,FeSO4\mathrm{FeC}_{2} \mathrm{O}_{4}, \mathrm{Fe}_{2}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}, \mathrm{FeSO}_{4} and Fe2(SO4)3\mathrm{Fe}_{2}\left(\mathrm{SO}_{4}\right)_{3} in acidic medium, the number of moles of KMnO4\mathrm{KMnO}_{4} required is :

  1. Option A:

    3

  2. Option B:

    2

    Correct
  3. Option C:

    5

  4. Option D:

    7

Answer: B

Step-by-step solution

Meq of KMnO4=meq\mathrm{KM}_{\mathrm{n}} \mathrm{O}_{4}=\mathrm{meq} of FeC2O4+meq\mathrm{FeC}_{2} \mathrm{O}_{4}+\mathrm{meq} of Fe2(C2O4)+\mathrm{Fe}_{2}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)+ meq of FeSO4\mathrm{FeSO}_{4} moles ×5=1×3+1×6+1×1\times 5=1 \times 3+1 \times 6+1 \times 1 moles =105=2=\frac{10}{5}=2

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Redox Reactions
Topic
n-Factor, Redox Titrations, Self Indicator & Miscellaneous Cases
In order to oxidise a mixture of 1 mole each of FeC 2 O 4 , Fe 2 ( C… | JEE Main 2026 PYQ with Solution · DhiX AI