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Chemistry · Thermodynamics & Thermochemistry

JEE Main 2026 — 4 April, Morning Shift — Question 51

Given below are two statements:

Statement I: For an ideal gas, heat capacity at constant volume is always greater than the heat capacity at constant pressure.

Statement II : In a constant volume process, no work is produced and all the heat withdrawn goes into the chaotic motion and is reflected by a temperature increase of the ideal gas.

In the light of the above statements, choose the correct answer from the options given below:

  1. Option A:

    Both Statement I and Statement II are true

  2. Option B:

    Both Statement I and Statement II are false

  3. Option C:

    Statement I is true but Statement II is false

  4. Option D:

    Statement I is false but Statement II is true

    Correct

Answer: D

Step-by-step solution

From first law of thermodynamics ΔU=q+w\Delta \mathrm{U}=\mathrm{q}+\mathrm{w} constant volume w=0\mathrm{w}=0 ΔU=q\Delta \mathrm{U}=\mathrm{q} Also CP=CV+R\mathrm{C}_{\mathrm{P}}=\mathrm{C}_{\mathrm{V}}+\mathrm{R} CP=\mathrm{C}_{\mathrm{P}}= heat capacity at constant pressure Cv=\mathrm{C}_{\mathrm{v}}= Heat capacity at constant volume. R=\mathrm{R}= constant

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
4 April, Morning Shift
Subject
Chemistry
Chapter
Thermodynamics & Thermochemistry
Topic
Introduction to Terminology in Thermodynamics
Given below are two statements: Statement I: For an ideal gas, heat… | JEE Main 2026 PYQ with Solution · DhiX AI