Chemistry · Redox Reactions
JEE Main 2026 — 2 April, Morning Shift — Question 46
An electrochemical cell is constructed using half cells in the direction of spontaneous change and Which of the following option is correct?
- Option A:Correct
Overall reaction \mathrm{Fe}(\mathrm{s})+2 \mathrm{OH}^{1}(\mathrm{aq})+2 \mathrm{AgBr}(\mathrm{s})$$\rightleftharpoons \mathrm{Fe}(\mathrm{OH})_{2}(\mathrm{~s})+2 \mathrm{Ag}(\mathrm{s})+2 \mathrm{Br}^{-}(\mathrm{aq})
- Option B:
- Option C:
Fe is reduced in the electrochemical cell
- Option D:
is an extensive property
Answer: A
Step-by-step solution
Overall reaction
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2026
- Subject
- Chemistry
- Chapter
- Redox Reactions
- Topic
- n-Factor, Redox Titrations, Self Indicator & Miscellaneous Cases