A vernier callipers has 20 divisions on the vernier scale, which coincides with 19 th division on the main scale. The least count of the instrument is 0.1 mm . One main scale division is equal to mm .

Physics · Units, Dimensions & Error Analysis

JEE Main 2024 — 5 April, Shift 2 — Question 46

A vernier callipers has 20 divisions on the vernier scale, which coincides with $19^{\text {th }}$ division on the main scale. The least count of the instrument is 0.1 mm . One main scale division is equal to $\qquad$ mm .

Option A:
1
Option B:
0.5
Option C:
2
Correct
Option D:
5

Answer: C

Step-by-step solution

$20 \mathrm{VSD}=19 \mathrm{MSD}$

$1 \mathrm{VSD}=\frac{19}{20} \mathrm{MSD}$

L.C. $=1 \mathrm{MSD}-1 \mathrm{VSD}$

$0.1 \mathrm{~mm}=1 \mathrm{MSD}-\frac{19}{20} \mathrm{MSD}$

$0.1=\frac{1}{20} \mathrm{MSD}$

$1 \mathrm{MSD}=2 \mathrm{~mm}$

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Exam: JEE Main 2024
Paper: 5 April, Shift 2
Subject: Physics
Chapter: Units, Dimensions & Error Analysis
Topic: Vernier Calipers and Screw Gauge

What is the dimensional formula of ab^-1 in the equation ( P+frac a V^2 )( V- b)= RT , where letters have their usual meaning.

Answer: C

Step-by-step solution

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