Physics · Mechanical Properties of Matter
JEE Main 2024 — 5 April, Shift 2 — Question 45
Match List-I with List-II :
| List-I | List-II | ||
|---|---|---|---|
| (A) | A force that restores an elastic body of unit area to its original state | (I) | Bulk modulus |
| (B) | Two equal and opposite forces parallel to opposite faces | (II) | Young's modulus |
| (C) | Forces perpendicular everywhere to the surface per unit area same everywhere | (III) | Stress |
| (D) | Two equal and opposite forces perpendicular to opposite faces | (IV) | Shear modulus |
{l} A force Choose the correct answer from the options given below :
- Option A:
(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- Option B:
(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
- Option C:Correct
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- Option D:
(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
Answer: C
Step-by-step solution
(A) stress
If
Stress
(A)-(III) (B)
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2024
- Paper
- 5 April, Shift 2
- Subject
- Physics
- Chapter
- Mechanical Properties of Matter
- Topic
- Stress,Strain and Modulus of Elasticity