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Physics · Friction

JEE Main 2024 — 5 April, Shift 2 — Question 47

A heavy box of mass 50 kg is moving on a horizontal surface. If co-efficient of kinetic friction between the box and horizontal surface is 0.3 then force of kinetic friction is :

  1. Option A:

    14.7 N

  2. Option B:

    147 N

    Correct
  3. Option C:

    1.47

  4. Option D:

    1470

Answer: B

Step-by-step solution

Fk=μkN=0.3×50×9.8=147 N\mathrm{F}_{\mathrm{k}}=\mu_{\mathrm{k}} \mathrm{N}=0.3 \times 50 \times 9.8=147 \mathrm{~N}

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
5 April, Shift 2
Subject
Physics
Chapter
Friction
Topic
Single Block Problems Involving Friction
A heavy box of mass 50 kg is moving on a horizontal surface. If… | JEE Main 2024 PYQ with Solution · DhiX AI