Physics · Geometrical Optics

JEE Main 2025 — 2 April, Morning Shift — Question 64

A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object ' $O$ ', is ( $C$ is the center of curvature of the spherical surface and $R$ is the radius of curvature)

Option A:
0.4 m left to the spherical surface
Correct
Option B:
0.24 m left to the spherical surface
Option C:
0.24 m right to the spherical surface
Option D:
0.4 m right to the spherical surface

Answer: A

Step-by-step solution

For spherical surfaces

\begin{aligned} & \frac{\mu_{2}}{v}-\frac{\mu_{1}}{u}=\frac{\mu_{2}-\mu_{1}}{R} & \\ \frac{1.5}{v}-\frac{1}{-0.2}=\frac{0.5}{0.4} & \\ v=-0.4 \mathrm{~m} \end{aligned}

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 2 April, Morning Shift
Subject: Physics
Chapter: Geometrical Optics
Topic: Refraction at Curved Surface and Glass Sphere