Physics · Motion in one Dimension

JEE Main 2025 — 2 April, Morning Shift — Question 65

A person travelling on a straight line moves with a uniform velocity $v_{1}$ for a distance $x$ and with a uniform velocity $v_{2}$ for the next $\frac{3}{2} x$ distance. The average velocity in this motion is $\frac{50}{7} \mathrm{~m} / \mathrm{s}$ . If $v_{1}$ is $5 \mathrm{~m} / \mathrm{s}$ then $v_{2}=$ $\qquad$ $\mathrm{m} / \mathrm{s}$ .

Answer: 10

Numerical answer — enter this value.

Step-by-step solution

$v_{\mathrm{avg}}=\frac{x+\frac{3 x}{2}}{\frac{x}{5}+\frac{3 x}{2 v_{2}}}=\frac{50}{7}$

$v_{2}=10 \mathrm{~m} / \mathrm{s}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 2 April, Morning Shift
Subject: Physics
Chapter: Motion in one Dimension
Topic: Uniformly Accelerated Motion