Physics · Geometrical Optics

JEE Main 2025 — 2 April, Evening Shift — Question 67

A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to

60∘60^{\circ}. The refractive index of the prism material is 2\sqrt{2}.

The angle of incidence (in degrees) is \qquad -

Answer: 45

Numerical answer — enter this value.

Step-by-step solution

For minimum deviation

r1=r2=A2=30∘r_{1}=r_{2}=\frac{A}{2}=30^{\circ} At PP

1×sin⁡i=μ×sin⁡301 \times \sin i=\mu \times \sin 30

sin⁡i=2×12=12\sin i=\sqrt{2} \times \frac{1}{2}=\frac{1}{\sqrt{2}}

i=45∘i=45^{\circ}

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Geometrical Optics
Topic
Apparent Depth, Glass Slab, Prism and Dispersion
A ray of light suffers minimum deviation when incident on a prism… | JEE Main 2025 PYQ with Solution · DhiX AI