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Physics · Geometrical Optics

JEE Main 2025 — 2 April, Evening Shift — Question 59

Two identical objects are placed in front of convex mirror and concave mirror having same radii of curvature of 12 cm , at same distance of 18 cm from the respective mirrors. The ratio of sizes of the images formed by convex mirror and by concave mirror is:

  1. Option A:

    2

  2. Option B:

    3

  3. Option C:

    13\frac{1}{3}

  4. Option D:

    12\frac{1}{2}

    Correct

Answer: D

Step-by-step solution

m=(ff−u)m=\left(\frac{f}{f-u}\right)

hi=mh0h_{i}=m h_{0}

hi1hi2=(f1f1−u)(f2−uf2)\frac{h_{i_{1}}}{h_{i_{2}}}=\left(\frac{f_{1}}{f_{1}-u}\right)\left(\frac{f_{2}-u}{f_{2}}\right)

f1=6,f2=−6f_{1}=6, f_{2}=-6

u=−18u=-18

=624×(12)(−6)=\frac{6}{24} \times \frac{(12)}{(-6)}

∣hi1hi2∣=∣−12∣=12\left|\frac{h_{i_{1}}}{h_{i_{2}}}\right|=\left|\frac{-1}{2}\right|=\frac{1}{2}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
2 April, Evening Shift
Subject
Physics
Chapter
Geometrical Optics
Topic
Reflection of Light at Curved Surfaces and Spherical Mirrors

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