JEE Main 2026 — 4 April, Morning Shift — Question 22

$\vec{a}=\vec{F}/m = t\hat{i}+3t^2\hat{j}$. $\vec{v}=\int_0^2 \vec{a} dt = [t^2/2 \hat{i}+t^3\hat{j}]_0^2 = 2\hat{i}+8\hat{j}$. $\vec{F}(t=2)=4\hat{i}+24\hat{j}$. Power = \vec{F}\cdot\vec{v}=4×2+24×8=8+192=200 W