Physics · Alternating Current

JEE Main 2026 — 4 April, Morning Shift — Question 23

An inductor of 10 mH, capacitor 0.1 μF and resistor 100 Ω are connected in series across an AC supply 220 V, 70 Hz. The power factor is 0.5. The difference between inductive reactance and capacitive reactance is $\sqrt{3}\alpha$ Ω. The value of $\alpha$ is ______.

Answer: 100

Numerical answer — enter this value.

Step-by-step solution

cosφ=0.5 ⇒ φ=60°, tanφ = |X_L-X_C|/R = √3 ⇒ |X_L-X_C| = R√3 = 100√3 = √3 α ⇒ α=100

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 4 April, Morning Shift
Subject: Physics
Chapter: Alternating Current
Topic: Series L-R, R-C, L-C Circuits with AC Source