Physics · Work, Power & Energy

JEE Main 2026 — 4 April, Morning Shift — Question 19

A 1 kg block is subjected to two simultaneous forces $(2\hat{i}+3\hat{j}+4\hat{k})$ N and $(3\hat{i}-\hat{j}-2\hat{k})$ N and is moved a distance of 25 m along $(3\hat{i}-4\hat{j})$ direction. The work done in this process is ______ J.

Answer: 35

Numerical answer — enter this value.

Step-by-step solution

Net force = $5\hat{i}+2\hat{j}+2\hat{k}$ N. Displacement = $75\hat{i}-100\hat{j}$ m (since 25 m along 3i-4j gives components 75i-100j). Work = 5×75 + 2×(-100) + 2×0 = 375 -200 = 175? Wait recalc: Displacement vector = 25 * (3i-4j)/5 = 15i -20j. Then work = F·S = (5)(15) + (2)(-20) + (2)(0)=75-40=35 J. Answer 35

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Exam: JEE Main 2026
Paper: 4 April, Morning Shift
Subject: Physics
Chapter: Work, Power & Energy
Topic: Work Done by a Constant and Variable Force

A body of mass 2 kg begins to move under a time‑dependent force vecF=(2thati+6t^2hatj) N. The power produced by the force at t=2 s is W.

Answer: 35

Step-by-step solution

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