Physics · System Of Particles

JEE Main 2026 — 23 January, Evening Shift — Question 27

A body of mass 14 kg initially at rest explodes and breaks into three fragments of masses in the ratio $2: 2: 3$ . The two pieces of equal masses fly off perpendicular to each other with a speed of $18 \mathrm{~m} / \mathrm{s}$ each. The velocity of the heavier fragment is $\_\_\_\_$ $\mathrm{m} / \mathrm{s}$ .

Option A:
$10 \sqrt{2}$
Option B:
$12 \sqrt{2}$
Correct
Option C:
12
Option D:
$24 \sqrt{2}$

Answer: B

Step-by-step solution

Apply C.O.M $\mathrm{M}_{1} \mathrm{~V}_{1}+\mathrm{M}_{2} \mathrm{~V}_{2}+\mathrm{M}_{3} \mathrm{~V}_{3}=0$ $2(-18 \mathrm{i})+2(-18 \mathrm{j})+3 \mathrm{~V}_{3}=0$ $\mathrm{V}_{3}=12 \mathrm{i}+12 \mathrm{j}$ $\left|\mathrm{V}_{3}\right|=12 \sqrt{2} \mathrm{~m} / \mathrm{s}$

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Exam: JEE Main 2026
Paper: 23 January, Evening Shift
Subject: Physics
Chapter: System Of Particles
Topic: Conservation of Linear Momentum