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Physics · Moving Charges and Magnetic Field

JEE Main 2026 — 23 January, Evening Shift — Question 28

The current passing through a conducting loop in the form of equilateral triangle of side 43 cm4 \sqrt{3} \mathrm{~cm} is 2A. The magnetic field at its centroid is α×10−5 T\alpha \times 10^{-5} \mathrm{~T}. The value of α\alpha is ____\_\_\_\_ . (Given : μo=4π×10−7\mu_{\mathrm{o}}=4 \pi \times 10^{-7} SI units)

  1. Option A:

    232 \sqrt{3}

  2. Option B:

    3\sqrt{3}

  3. Option C:

    333 \sqrt{3}

    Correct
  4. Option D:

    32\frac{\sqrt{3}}{2}

Answer: C

Step-by-step solution

B=μ04π×Id[sin⁡60∘+sin⁡60∘]×3B=\frac{\mu_{0}}{4 \pi} \times \frac{I}{d}\left[\sin 60^{\circ}+\sin 60^{\circ}\right] \times 3 B=10−7×22×10−2(32+32)×3\mathrm{B}=10^{-7} \times \frac{2}{2 \times 10^{-2}}\left(\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}\right) \times 3 =3×10−5×3=33×10−5=\sqrt{3} \times 10^{-5} \times 3=3 \sqrt{3} \times 10^{-5}

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
23 January, Evening Shift
Subject
Physics
Chapter
Moving Charges and Magnetic Field
Topic
Magnetic Field Due to Current-Carrying Wire - Biot-Savart Law
The current passing through a conducting loop in the form of… | JEE Main 2026 PYQ with Solution · DhiX AI