Experiment No. [ A ] ( mol \; dm -3 ) [ B ] ( mol \; dm -3 ) [ C ] ( mol \; dm -3 ) Rate of reaction ( mol \; dm -3 s -1 ) --- --- --- --- --- 1 0.2 0.1 0.1 6.0 × 10 -5 2 0.2 0.2 0.1 6.0 × 10 -5 3 0.2 0.1 0.2 1.2 × 10 -5 4 0.3 0.1 0.1 9.0 × 10 -5 The rate of the reaction for [ A ]=0.15 mol dm -3 ,[ B ]=0.25 mol dm -3 and [ C ]=0.15 mol dm -3 is found to be Y × 10 -5 mol dm -3 s -1 . The value of Y is

Chemistry · Chemical Kinetics

JEE Advanced 2019 — Paper 1 — Question 27

Experiment No.	$[\mathrm{A}]$ $\left(\mathrm{mol} \; \mathrm{dm}^{-3}\right)$	$[\mathrm{B}]$ $\left(\mathrm{mol} \; \mathrm{dm}^{-3}\right)$	$[\mathrm{C}]$ $\left(\mathrm{mol} \; \mathrm{dm}^{-3}\right)$	Rate of reaction $\left(\mathrm{mol} \; \mathrm{dm}^{-3} \mathrm{~s}^{-1}\right)$
1	0.2	0.1	0.1	$6.0 \times 10^{-5}$
2	0.2	0.2	0.1	$6.0 \times 10^{-5}$
3	0.2	0.1	0.2	$1.2 \times 10^{-5}$
4	0.3	0.1	0.1	$9.0 \times 10^{-5}$

The rate of the reaction for $[\mathrm{A}]=0.15 \mathrm{~mol} \mathrm{dm}^{-3},[\mathrm{~B}]=0.25 \mathrm{~mol} \mathrm{dm}^{-3}$ and

$[\mathrm{C}]=0.15 \mathrm{~mol} \mathrm{dm}^{-3}$ is found to be $\mathrm{Y} \times 10^{-5} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}$ . The value of Y is

Answer: 6.75

Numerical answer — enter this value.

Step-by-step solution

Rate $\mathrm{k}[\mathrm{A}]^{\mathrm{x}}[\mathrm{B}]^{\mathrm{y}}[\mathrm{C}]^{\mathrm{z}}$

By exp. No. $1 \& 2 \quad y=0$

By exp. No. $1 \& 3 \quad z=1$

By exp. No. $1 \& 4 \quad x=1$

Rate $=\mathrm{k}[\mathrm{A}]^{1}[\mathrm{~B}]^{0}[\mathrm{C}]^{1}$

From Exp. No. $1 \quad 6 \times 10^{-5}=\mathrm{k}(0.2)(0.1)$

$\Rightarrow \mathrm{k}=3 \times 10^{-3}$

Now for $[\mathrm{A}]=0.15$ $[B]=0.25$ $[C]=0.15$

Rate $=\mathrm{k}[\mathrm{A}]^{1}[\mathrm{~B}]^{0}[\mathrm{C}]^{1}$

$=3 \times 10^{-3} \times 0.15 \times 1 \times 0.15$

=3 \times 0.0225 \times 10^{-3}=\underbrace{6.75}_{\mathrm{Y}} \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{sec}^{-1}

Answer key and solution verified before publishing.

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Exam: JEE Advanced 2019
Paper: Paper 1
Subject: Chemistry
Chapter: Chemical Kinetics
Topic: Rate Laws and Rate Constant