Physics · Atomic Physics

NEET (UG) 2023 — Question 2

The work functions of Caesium (Cs), Potassium ( K ) and Sodium ( Na ) are 2.14 eV , 2.30 eV and 2.75 eV respectively. If incident electromagnetic radiation has an incident energy of 2.20 eV , which of these photosensitive surfaces may emit photoelectrons?

  1. Option A:

    Both Na and K

  2. Option B:

    K only

  3. Option C:

    Na only

  4. Option D:

    Cs only

    Correct

Answer: D

Step-by-step solution

Energy of incident radiation =2.80eV=2.80 \mathrm{eV} Work function of Cs→2.14eV\mathrm{Cs} \rightarrow 2.14 \mathrm{eV} Work function of K→2.30eV\mathrm{K} \rightarrow 2.30 \mathrm{eV} Work function of Na→2.75eV\mathrm{Na} \rightarrow 2.75 \mathrm{eV} Since the work function of potassium and sodium are more than energy of incident radiation hence

photons may be emitted from caesium.

Answer key and solution verified before publishing.

Practise Atomic Physics

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
NEET (UG) 2023
Subject
Physics
Chapter
Atomic Physics
Topic
Photoelectric Effect
The work functions of Caesium (Cs), Potassium ( K ) and Sodium ( Na )… | NEET (UG) 2023 PYQ with Solution · DhiX AI