Physics · Rotational Dynamics

NEET (UG) 2025 — Question 16

The Sun rotates around its centre once in 27 days. What will be the period of revolution if the Sun were to expand to twice its present radius without any external influence? Assume the Sun to be a sphere of uniform density.

  1. Option A:

    100 days

  2. Option B:

    105 days

  3. Option C:

    115 days

  4. Option D:

    108 days

    Correct

Answer: D

Step-by-step solution

Angular Momentum conservation

I1ω1=I2ω2\mathrm{I}_{1} \omega_{1}=\mathrm{I}_{2} \omega_{2} \quad M=\mathrm{M}= same

ω2=ω14\omega_{2}=\frac{\omega_{1}}{4} \quad R2=2r1\mathrm{R}_{2}=2 \mathrm{r}_{1}

T=2πωT=\frac{2 \pi}{\omega} \quad I∝r2\mathrm{I} \propto \mathrm{r}^{2}

 T2=4 T1=4×27\mathrm{~T}_{2}=4 \mathrm{~T}_{1}=4 \times 27 \quad I2=4I1\mathrm{I}_{2}=4 \mathrm{I}_{1}

 T2=108\mathrm{~T}_{2}=108 days

T1=27\mathrm{T}_{1}=27 day

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2025
Subject
Physics
Chapter
Rotational Dynamics
Topic
Angular Momentum and its Conservation
The Sun rotates around its centre once in 27 days. What will be the… | NEET (UG) 2025 PYQ with Solution · DhiX AI