Chemistry · Alkyl and Aryl Halides

NEET (UG) 2024 — Question 83

The products AA and BB obtained in the following reactions, respectively, are

3ROH+PCl3→3RCl+A3 \mathrm{ROH}+\mathrm{PCl}_{3} \rightarrow 3 \mathrm{RCl}+\mathrm{A}

ROH+PCl5→RCl+HCl+B\mathrm{ROH}+\mathrm{PCl}_{5} \rightarrow \mathrm{RCl}+\mathrm{HCl}+\mathrm{B}

  1. Option A:

    POCl3\mathrm{POCl}_{3} and H3PO3\mathrm{H}_{3} \mathrm{PO}_{3}

  2. Option B:

    POCl3\mathrm{POCl}_{3} and H3PO4\mathrm{H}_{3} \mathrm{PO}_{4}

  3. Option C:

    H3PO4\mathrm{H}_{3} \mathrm{PO}_{4} and POCl3\mathrm{POCl}_{3}

  4. Option D:

    H3PO3\mathrm{H}_{3} \mathrm{PO}_{3} and POCl3\mathrm{POCl}_{3}

    Correct

Answer: D

Step-by-step solution

With PClX3\ce{PCl3}, three alkyl groups replace three Cl\ce{Cl} atoms: 3 ROH+PClX3→3 RCl+HX3POX3\ce{3 ROH + PCl3 -> 3 RCl + H3PO3}. Thus A=HX3POX3A = \ce{H3PO3}. With PClX5\ce{PCl5}, one Cl\ce{Cl} forms the alkyl chloride and another forms HCl\ce{HCl}: ROH+PClX5→RCl+HCl+POClX3\ce{ROH + PCl5 -> RCl + HCl + POCl3}. Thus B=POClX3B = \ce{POCl3}. Therefore the correct pair is HX3POX3\ce{H3PO3} and POClX3\ce{POCl3}, i.e. option D.

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2024
Subject
Chemistry
Chapter
Alkyl and Aryl Halides
Topic
Introduction to Alkyl Halides and Methods of Preparation
The products A and B obtained in the following reactions… | NEET (UG) 2024 PYQ with Solution · DhiX AI