Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

NEET (UG) 2024 — Question 54

The highest number of helium atoms is present in:

  1. Option A:

    4 mol of helium

    Correct
  2. Option B:

    4 u of helium

  3. Option C:

    4 g of helium

  4. Option D:

    2.27 L of helium at STP

Answer: A

Step-by-step solution

(1) 4 mol of He=4 NA  He\mathrm{He}=4 \mathrm{~N}_{\mathrm{A}} \;\mathrm{He} atoms

(2) 4 u of He=4u4u=1\mathrm{He}=\frac{4 u}{4 u}=1 He atom

(3) 4 g of Helium =4 g4 g=\frac{4 \mathrm{~g}}{4 \mathrm{~g}} mole =1=1 mole =NA=\mathrm{N}_{\mathrm{A}} He atom

(4) 2.27 L of He at STP =2.2722.4=\frac{2.27}{22.4} mole =0.1 mole =0.1 \text { mole }

=0.1 NA  He   atom =0.1\mathrm{~N}_{\mathrm{A}} \;\mathrm{He} \;\text { atom }

Answer key and solution verified before publishing.

Practise Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
NEET (UG) 2024
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Introduction to Mole Concept
The highest number of helium atoms is present in: | NEET (UG) 2024 PYQ with Solution · DhiX AI