The energy of an electron in the ground state (n=1) for He + ion is -x J , then that for an electron in n=2 state for Be 3+ ion in J is

Chemistry · Structure of Atom

NEET (UG) 2024 — Question 56

The energy of an electron in the ground state $(n=1)$ for $\mathrm{He}^{+}$ ion is $-x J$ , then that for an electron in $n=2$ state for $\mathrm{Be}^{3+}$ ion in J is

Option A:
$-x$
Correct
Option B:
$-\frac{x}{9}$
Option C:
$-4 x$
Option D:
$-\frac{4}{9} x$

Answer: A

Step-by-step solution

$E_n = -R_H \left( \frac{Z^2}{n^2} \right) J$ $\text{For He}^+ (n = 1),$ $E_n = -x = -R_H \left( \frac{2^2}{1^2} \right) = -4R_H$ $\therefore \quad R_H = \frac{x}{4}$ $\text{For Be}^{3+} (n = 2),$ $E_n = -R_H \left( \frac{Z^2}{n^2} \right) J$ $= -\frac{x}{4} \times \left( \frac{4 \times 4}{2 \times 2} \right) = -x \text{ J}$

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Exam: NEET (UG) 2024
Paper: 2024 paper
Subject: Chemistry
Chapter: Structure of Atom
Topic: Bohr's Model of Atom

Match List I with List II List I (Quantum Number) List II (Information provided) --- --- A. m I. Shape of orbital B. m 2 II. Size of…

Answer: A

Step-by-step solution

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