The conductivity of centimolar solution of KCl at 25 ° C is 0.0210 ohm -1 cm -1 and the resistance of the cell containing the solution at 25 ° C is 60 ohm . The value of cell constant is -

Chemistry · Electrochemistry

NEET (UG) 2023 — Question 62

The conductivity of centimolar solution of KCl at $25^{\circ} \mathrm{C}$ is $0.0210 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$ and the resistance of the cell containing the solution at $25^{\circ} \mathrm{C}$ is 60 ohm . The value of cell constant is -

Option A:
$3.28 \mathrm{~cm}^{-1}$
Option B:
$1.26 \mathrm{~cm}^{-1}$
Correct
Option C:
$3.34 \mathrm{~cm}^{-1}$
Option D:
$1.34 \mathrm{~cm}^{-1}$

Answer: B

Step-by-step solution

Conductivity $=$ conductance $\times$ cell constant

\begin{aligned} k & =G G^* \\ & =\frac{1}{R} G^* \\ G^* & =k \times R=0.0210 \times 60=1.26 \mathrm{~cm}^{-1} \end{aligned}

Answer key and solution verified before publishing.

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Exam: NEET (UG) 2023
Paper: 2023 paper
Subject: Chemistry
Chapter: Electrochemistry
Topic: Conductance of Solutions and Kohlrausch's Law