Chemistry · Electrochemistry

NEET (UG) 2024 — Question 88

Mass in grams of copper deposited by passing 9.6487 A current through a voltameter containing copper sulphate solution for 100 seconds is (Given : Molar mass of $Cu :63\, g\, mol^{-1}, 1\, F =96487\,C$ )

Option A:
3.15 g
Option B:
0.315 g
Correct
Option C:
31.5 g
Option D:
0.0315 g

Answer: B

Step-by-step solution

$\mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}(\mathrm{s})$

$\text { Mass of Cu deposited }(w) =\frac{M \times i \times t}{n F}$

$=\frac{63 \times 9.6487 \times 100}{2 \times 96487}$

$=0.315 \mathrm{~g}$

Answer key and solution verified before publishing.

Practise Electrochemistry

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: NEET (UG) 2024
Paper: 2024 paper
Subject: Chemistry
Chapter: Electrochemistry
Topic: Faraday's Laws

Match List I with List II. List I (Conversion) List II (Number of Faraday required) --- --- A. 1 mol of H 2 O to O 2 I. 3F B. 1 mol of MnO…

Answer: B

Step-by-step solution

Practise Electrochemistry

More Electrochemistry questions from this paper