In an ideal transformer, the turns ratio is frac N P N S =1/2 . The ratio V S : V P is equal to (the symbols carry their usual meaning) :

Physics · Electromagnetic Induction

NEET (UG) 2024 — Question 29

In an ideal transformer, the turns ratio is $\frac{N_{P}}{N_{S}}=\frac{1}{2}$ . The ratio $V_{S}: V_{P}$ is equal to (the symbols carry their usual meaning) :

Option A:
$1: 2$
Option B:
$2: 1$
Correct
Option C:
$1: 1$
Option D:
$1: 4$

Answer: B

Step-by-step solution

For an ideal transformer, $\frac{V_S}{V_P} = \frac{N_S}{N_P}$ . Given $N_P:N_S = 1:2$ , so $\frac{N_S}{N_P} = 2:1$ . Therefore, $V_S:V_P = 2:1$ , which corresponds to option B.

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Exam: NEET (UG) 2024
Paper: 2024 paper
Subject: Physics
Chapter: Electromagnetic Induction
Topic: Eddy Currents, AC Generator and Transformers

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Step-by-step solution

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