Physics · Units, Dimensions & Error Analysis

NEET (UG) 2024 — Question 23

In a vernier callipers, $(N+1)$ divisions of vernier scale coincide with $N$ divisions of main scale. If 1 MSD represents 0.1 mm , the vernier constant (in cm ) is:

Option A:
$\frac{1}{10 \mathrm{~N}}$
Option B:
$\frac{1}{100(N+1)}$
Correct
Option C:
100 N
Option D:
$10(N+1)$

Answer: B

Step-by-step solution

$V . C=M S D-V S D…(1)$

given : $(N+1)$ VSD $=N$ MSD

VSD $=\left(\frac{N}{N+1}\right)$ MSD $…(2)$

From (1) and (2)

$V . C=(M S D)-\frac{N}{N+1}(M S D)$

$=\operatorname{MSD}\left(1-\frac{N}{N+1}\right)=\frac{M S D}{N+1}$

$=\frac{0.01}{N+1}=\frac{1}{100(N+1)}$

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Exam: NEET (UG) 2024
Paper: 2024 paper
Subject: Physics
Chapter: Units, Dimensions & Error Analysis
Topic: Vernier Calipers and Screw Gauge

Answer: B

Step-by-step solution

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