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Physics · Simple Harmonic Motion

NEET (UG) 2024 — Question 15

If x=5sin⁡(πt+π3) mx = 5\sin(\pi t + \frac{\pi}{3})\,\text{m} represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are

  1. Option A:

    5 cm,2 s5 \mathrm{~cm}, 2 \mathrm{~s}

  2. Option B:

    5 m,2 s5 \mathrm{~m}, 2 \mathrm{~s}

    Correct
  3. Option C:

    5 cm,1 s5 \mathrm{~cm}, 1 \mathrm{~s}

  4. Option D:

    5 m,1 s5 \mathrm{~m}, 1 \mathrm{~s}

Answer: B

Step-by-step solution

x=5sin⁡(πt+π3)mx=5 \sin \left(\pi t+\frac{\pi}{3}\right) m

Amplitude =5 m=5 \mathrm{~m}

ω=π=2πT\omega=\pi=\frac{2 \pi}{T}

T=2ππ=2 sT=\frac{2 \pi}{\pi}=2 \mathrm{~s}

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2024
Paper
2024 paper
Subject
Physics
Chapter
Simple Harmonic Motion
Topic
Kinematics of SHM, Phase and Energy in SHM

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