Chemistry · Redox Reactions

NEET (UG) 2025 — Question 51

Consider the following compounds:

KO‾2,H2O‾2\underline{\mathrm{KO}}_{2}, \mathrm{H}_{2} \underline{\mathrm{O}}_{2} and H2SO‾4\mathrm{H}_{2} \underline{\mathrm{SO}}_{4}.

The oxidation states of the underlined elements in them are, respectively,

  1. Option A:

    +1,−1+1,-1, and +6

    Correct
  2. Option B:

    +2,−2+2,-2, and +6

  3. Option C:

    +1,−2+1,-2, and +4

  4. Option D:

    +4,−4+4,-4, and +6

Answer: A

Step-by-step solution

KO2 Alkali metals always show +1 oxidation state in their compounds.

HX2OX2:2(+1)+2x=0⇒x=−1\ce{H2O2}: \quad 2(+1) + 2x = 0 \quad \Rightarrow \quad x = -1 HX2SOX4:2(+1)+x+4(−2)=0⇒x=+6\ce{H2SO4}: \quad 2(+1) + x + 4(-2) = 0 \quad \Rightarrow \quad x = +6

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2025
Subject
Chemistry
Chapter
Redox Reactions
Topic
n-Factor, Redox Titrations, Self Indicator & Miscellaneous Cases
Consider the following compounds: underline KO 2 , H 2 underline O 2… | NEET (UG) 2025 PYQ with Solution · DhiX AI