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Physics · Friction

NEET (UG) 2023 — Question 35

Calculate the maximum acceleration of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is 0.15( g=10 m s−2)0.15\left(\mathrm{~g}=10 \mathrm{~m} \mathrm{~s}^{-2}\right).

  1. Option A:

    150 m s−2150 \mathrm{~m} \mathrm{~s}^{-2}

  2. Option B:

    1.5 m s−21.5 \mathrm{~m} \mathrm{~s}^{-2}

    Correct
  3. Option C:

    50 m s−250 \mathrm{~m} \mathrm{~s}^{-2}

  4. Option D:

    1.2 m s−21.2 \mathrm{~m} \mathrm{~s}^{-2}

Answer: B

Step-by-step solution

mamax⁡=μsmgamax⁡=μsg=0.15×10=1.5 m/s2\begin{aligned} & m a_{\max }=\mu_s m g \\ & a_{\max }=\mu_s g=0.15 \times 10=1.5 \mathrm{~m} / \mathrm{s}^2\end{aligned}

Solution figure

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2023
Paper
2023 paper
Subject
Physics
Chapter
Friction
Topic
Single Block Problems Involving Friction
Calculate the maximum acceleration of a moving car so that a body… | NEET (UG) 2023 PYQ with Solution · DhiX AI