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Chemistry · Periodicity of Elements and Periodic Properties

NEET (UG) 2024 — Question 50

Arrange the following elements in increasing order of electronegativity:

N, O, F, C, Si

Choose the correct answer from the options given below:

  1. Option A:

    Si<C<N<O<F\mathrm{Si}<\mathrm{C}<\mathrm{N}<\mathrm{O}<\mathrm{F}

    Correct
  2. Option B:

    Si<C<O<N<F\mathrm{Si}<\mathrm{C}<\mathrm{O}<\mathrm{N}<\mathrm{F}

  3. Option C:

    O<F<N<C<Si\mathrm{O}<\mathrm{F}<\mathrm{N}<\mathrm{C}<\mathrm{Si}

  4. Option D:

    F<O<N<C<Si\mathrm{F}<\mathrm{O}<\mathrm{N}<\mathrm{C}<\mathrm{Si}

Answer: A

Step-by-step solution

Electronegativity increases across a period from left to right and decreases down a group. For the given elements: C and Si are in group 14, with Si below C, so Si<C\ce{Si} < \ce{C}. N, O, F are in period 2, with increasing electronegativity: N<O<F\ce{N} < \ce{O} < \ce{F}. Combining the orders: Si<C<N<O<F\ce{Si} < \ce{C} < \ce{N} < \ce{O} < \ce{F}. Thus, the correct option is A.

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2024
Paper
2024 paper
Subject
Chemistry
Chapter
Periodicity of Elements and Periodic Properties
Topic
Periodicity in Chemical Properties (Ionization Energy, Electron Affinity, Electronegativity)

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