An electric dipole is placed as shown in the figure. The electric potential (in 10 2 V ) at point P due to the dipole is (ε 0 = . permittivity of free space and frac 1 4 π ε 0 =K ):

Physics · Electrostatics

NEET (UG) 2023 — Question 44

An electric dipole is placed as shown in the figure. The electric potential (in $10^{2} \mathrm{~V}$ ) at point P due to the dipole is $\left(\epsilon_{0}=\right.$ permittivity of free space and $\frac{1}{4 \pi \epsilon_{0}}=K$ ):

Option A:
$\left(\frac{5}{8}\right) q K$
Option B:
$\left(\frac{8}{5}\right) \mathrm{qK}$
Option C:
$\left(\frac{8}{3}\right) q K$
Option D:
$\left(\frac{3}{8}\right) \mathrm{qK}$
Correct

Answer: D

Step-by-step solution

Electrostatic potential due to a point charge is given by $\frac{K q}{r}$

\begin{aligned} V_{\text {net at point } P} & =\frac{K q}{2 \times 10^{-2}}-\frac{K q}{8 \times 10^{-2}} \\ & =\frac{K q \times 10^2}{2}\left(1-\frac{1}{4}\right) \\ & =\left(\frac{3}{8} K q\right) \times 10^2 \mathrm{~V}=\frac{3}{8} q K \end{aligned}

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Exam: NEET (UG) 2023
Paper: 2023 paper
Subject: Physics
Chapter: Electrostatics
Topic: Electric Dipole

Answer: D

Step-by-step solution

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