Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

NEET (UG) 2025 — Question 63

Among the following choose the ones with equal number of atoms.

A. 212 g of Na2CO3( s)\mathrm{Na}_{2} \mathrm{CO}_{3}(\mathrm{~s}) [molar mass =106 g=106 \mathrm{~g} ]

B. 248 g of Na2O(s)\mathrm{Na}_{2} \mathrm{O}(\mathrm{s}) [molar mass =62 g=62 \mathrm{~g} ]

C. 240 g of NaOH(s)\mathrm{NaOH}(\mathrm{s}) [molar mass =40 g=40 \mathrm{~g} ]

D. 12 g of H2( g)\mathrm{H}_{2}(\mathrm{~g}) [molar mass =2 g=2 \mathrm{~g} ]

E. 220 g of CO2( g)\mathrm{CO}_{2}(\mathrm{~g}) [molar mass =44 g=44 \mathrm{~g} ]

Choose the correct answer from the options given below:

  1. Option A:

    A, B and C only

  2. Option B:

    A, B and D only

    Correct
  3. Option C:

    B, C and D only

  4. Option D:

    B, D and E only

Answer: B

Step-by-step solution

No. of atoms == Atomicity ×\times mole ×NA\times \mathrm{N}_{\mathrm{A}}

(A) No. of atoms =6×212106×NA=12 NA=6 \times \frac{212}{106} \times \mathrm{N}_{\mathrm{A}}=12 \mathrm{~N}_{\mathrm{A}}

(B) No. of atoms =3×24862×NA=12 NA=3 \times \frac{248}{62} \times \mathrm{N}_{\mathrm{A}}=12 \mathrm{~N}_{\mathrm{A}}

(C) No. of atoms =3×24040×NA=18 NA=3 \times \frac{240}{40} \times \mathrm{N}_{\mathrm{A}}=18 \mathrm{~N}_{\mathrm{A}}

(D) No. of atoms =2×122×NA=12 NA=2 \times \frac{12}{2} \times \mathrm{N}_{\mathrm{A}}=12 \mathrm{~N}_{\mathrm{A}}

(E) No. of atoms =3×22044×NA=15 NA=3 \times \frac{220}{44} \times \mathrm{N}_{\mathrm{A}}=15 \mathrm{~N}_{\mathrm{A}}

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2025
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Composition of Matter, Atoms, Molecules and Laws of Chemical Combination
Among the following choose the ones with equal number of atoms. A.… | NEET (UG) 2025 PYQ with Solution · DhiX AI