AB is a part of an electrical circuit (see figure). The potential difference " V A - V B ", at the instant when current i =2 A and is increasing at a rate of 1 amp / second is :

Physics · Electromagnetic Induction

NEET (UG) 2025 — Question 10

AB is a part of an electrical circuit (see figure). The potential difference " $\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}$ ", at the instant when current $\mathrm{i}=2 \mathrm{~A}$ and is increasing at a rate of $1 \mathrm{amp} /$ second is :

Option A:
5 volt
Option B:
6 volt
Option C:
9 volt
Option D:
10 volt
Correct

Answer: D

Step-by-step solution

Apply K.V.L.

$\mathrm{V}_{\mathrm{A}}-\frac{\mathrm{LdI}}{\mathrm{dt}}-5-\mathrm{IR}=\mathrm{V}_{\mathrm{B}}$

$\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=\frac{\mathrm{LdI}}{\mathrm{dt}}+5+\mathrm{IR}$

$=1 \times 1+5+2 \times 2$

$=1+5+4$

$=10 \mathrm{~V}$

Answer key and solution verified before publishing.

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Exam: NEET (UG) 2025
Paper: 2025 paper
Subject: Physics
Chapter: Electromagnetic Induction
Topic: L-R, L-C and L-C-R circuits with DC supply