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Physics · Current Electricity

NEET (UG) 2025 — Question 31

A wire of resistance RR is cut into 8 equal pieces. From these pieces two equivalent resistances are made by adding four of these together in parallel. Then these two sets are added in series. The net effective resistance of the combination is :

  1. Option A:

    R64\frac{\mathrm{R}}{64}

  2. Option B:

    R32\frac{\mathrm{R}}{32}

  3. Option C:

    R16\frac{\mathrm{R}}{16}

    Correct
  4. Option D:

    R8\frac{R}{8}

Answer: C

Step-by-step solution

Resistance of each part =R/8=\mathrm{R} / 8

Req =14(R/8)+14(R/8)=R16\mathrm{R}_{\text {eq }}=\frac{1}{4}(\mathrm{R} / 8)+\frac{1}{4}(\mathrm{R} / 8)=\frac{\mathrm{R}}{16}

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2025
Paper
2025 paper
Subject
Physics
Chapter
Current Electricity
Topic
Combination of Resistors and cells, Wheatstone Bridge

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