Physics · Electrostatics

NEET (UG) 2024 — Question 31

A thin spherical shell is charged by some source. The potential difference between the two points $C$ and $P$ (in V ) shown in the figure is:

(Take $\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9}$ SI units)

Answer: D

For uniformly charged spherical shell,

$V=\frac{k q}{R} \quad \quad \quad \text { For } r \leq R \text { ) }$

$\therefore \quad V_{C}=V_{P}$

$V_{C}-V_{P}=\text { Zero }$

Answer key and solution verified before publishing.

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