Physics · Geometrical Optics

NEET (UG) 2024 — Question 48

A small telescope has an objective of focal length 140 cm and an eye piece of focal length 5.0 cm . The magnifying power of telescope for viewing a distant object is:

  1. Option A:

    34

  2. Option B:

    28

    Correct
  3. Option C:

    17

  4. Option D:

    32

Answer: B

Step-by-step solution

f0=140 cmf_{0}=140 \mathrm{~cm} and fe=5 cmf_{e}=5 \mathrm{~cm}

For distant object,

m=f0fe=1405=28m=\frac{f_{0}}{f_{e}}=\frac{140}{5}=28

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2024
Subject
Physics
Chapter
Geometrical Optics
Topic
Optical Instruments
A small telescope has an objective of focal length 140 cm and an eye… | NEET (UG) 2024 PYQ with Solution · DhiX AI