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Physics · Units, Dimensions & Error Analysis

NEET (UG) 2025 — Question 39

A physical quantity PP is related to four observations a,b,ca, b, c and dd as follows :

P=a3b2/cdP=a^{3} b^{2} / c \sqrt{d}

The percentage errors of measurement in a,b,ca, b, c and dd are 1%,3%,2%1 \%, 3 \%, 2 \% and 4%4 \% respectively. The percentage error in the quantity PP is

  1. Option A:

    10%10 \%

  2. Option B:

    2%2 \%

  3. Option C:

    13%13 \%

    Correct
  4. Option D:

    15%15 \%

Answer: C

Step-by-step solution

P=a3b2c−1d−1/2P=a^{3} b^{2} c^{-1} d^{-1 / 2} (ΔPP×100)=(3Δaa+2Δ b b+1Δcc+123Δ d d)×100\left(\frac{\Delta \mathrm{P}}{\mathrm{P}} \times 100\right)=\left(\frac{3 \Delta \mathrm{a}}{\mathrm{a}}+\frac{2 \Delta \mathrm{~b}}{\mathrm{~b}}+\frac{1 \Delta \mathrm{c}}{\mathrm{c}}+\frac{1}{2} \frac{3 \Delta \mathrm{~d}}{\mathrm{~d}}\right) \times 100

=3(1%)+2(3%)+1(2%)+12(4%)=3(1 \%)+2(3 \%)+1(2 \%)+\frac{1}{2}(4 \%)

=13%= 13\%

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2025
Paper
2025 paper
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Significant Figures and Error Analysis

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