Physics · Motion in one Dimension

NEET (UG) 2023 — Question 37

A horizontal bridge is built across a river. A student standing on the bridge throws a small ball vertically upwards with a velocity 4 m s−14 \mathrm{~m} \mathrm{~s}^{-1}. The ball strikes the water surface after 4 s . The height of bridge above water surface is (Take g=10 m s−2\mathrm{g}=10 \mathrm{~m} \mathrm{~s}^{-2} ):

  1. Option A:

    60 m

  2. Option B:

    64 m

    Correct
  3. Option C:

    68 m

  4. Option D:

    56 m

Answer: B

Step-by-step solution

s=ut−12gt2=16−12×10×16=−64 m\begin{aligned} s & =u t-\frac{1}{2} g t^2 \\ & =16-\frac{1}{2} \times 10 \times 16 \\ & =-64 \mathrm{~m} \end{aligned}

Height of bridge above water surface =64 m=64 \mathrm{~m}

Solution figure

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2023
Subject
Physics
Chapter
Motion in one Dimension
Topic
Motion Under Gravity
A horizontal bridge is built across a river. A student standing on… | NEET (UG) 2023 PYQ with Solution · DhiX AI